Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyShowing how to graph a simple quadratic with 5 pointsStep by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method y=3x4;y=x2 Tiger Algebra Solver
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Y=x^2-4x+7-Allow me to jump back on my soap box This question demonstrates an all too common misunderstanding by math students that is perpetuated by textbooks that ask questions like this one Question > How do you determine if mathx^2y^2=4/math is aSince it is so simple to find the yintercept (and it will probably be a point in my Tchart anyway), they are only asking for the xintercepts this timeTo find the xintercept, I set y equal 0 and solve
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Graph a function by translating the parent functionSolution for x^2y=4 equation Simplifying x 2 1y = 4 Solving x 2 1y = 4 Solving for variable 'x' Move all terms containing x to the left, all other terms to the right Add 'y' to each side of the equation x 2 1y y = 4 y Combine like terms 1y y = 0 x 2 0 = 4 y x 2 = 4 y Simplifying x 2 = 4 y Reorder the terms 4 x 2 1y = 4 y 4 1y Reorder the terms 4Graph x^2y^2=4 x2 − y2 = 4 x 2 y 2 = 4 Find the standard form of the hyperbola Tap for more steps Divide each term by 4 4 to make the right side equal to one x 2 4 − y 2 4 = 4 4 x 2 4 y 2 4 = 4 4 Simplify each term in the equation in order to set the right side equal to 1 1 The standard form of an ellipse or hyperbola requires
Check x 4 is the square of x 2 Check y 4 is the square of y 2 Factorization is (x 2 y 2) • (x 2 y 2) Trying to factor as a Difference of Squares 32 Factoring x 2 y 2 Check x 2 is the square of x 1 Check y 2 is the square of y 1 Factorization is (x y) • (xDivide 0 0 by 4 4 Multiply − 1 1 by 0 0 Add − 4 4 and 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k kTo find the xintercept (s), substitute in 0 0 for y y and solve for x x Solve the equation Tap for more steps Rewrite the equation as − x 2 4 = 0 x 2 4 = 0 Subtract 4 4 from both sides of the equation Tap for more steps Multiply each term in − x 2 = − 4 x 2 = 4 by − 1 1
Get stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Step 4 Pulling out like terms 41 Pull out like factors 4y 4xy = 4y • (x 1) Equation at the end of step 4 4y • (x 1) = 0 Step 5 Theory Roots of a product 51 A product of several terms equals zero When a product of two or more terms equals y = x 2 4 Compare it to standard form of parabola y = a x 2 bx c a = 1 , b = 0, c = 4 We know that parabola like a curve a is positive , so the parabola opens upward The parabola giving us all real numbers is the domain To find the range
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All equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}4xy5=0 x 2 4 x − y − 5 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, andQuestion graphing by equations linears xy=4 xy=2 Answer by mananth () ( Show Source ) You can put this solution on YOUR website!Free quadratic equation calculator Solve quadratic equations using factoring, complete the square and the quadratic formula stepbystep
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Simple and best practice solution for x2y4=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreSteps to graph x^2 y^2 = 4
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The equation is now solved x^ {2}4x4=y Swap sides so that all variable terms are on the left hand side \left (x2\right)^ {2}=y Factor x^ {2}4x4 In general, when x^ {2}bxc is a perfect square, it can always be factored as \left (x\frac {b} {2}\right)^ {2}Find the xintercepts and vertex of y = –x 2 – 4x 2;4 Write x 25x as x^25*x 3 Use paranthesis() while performing arithmetic operations Eg1 Write sinxcosxtanx as sin(x)cos(x)tan(x) 2 Write secx*tanx as sec(x)*tan(x) 3 Write tanx/sinx as tan(x)/sin(x) 4 Use inv to specify inverse and ln to specify natural log respectively Eg1 Write
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By using Pythagoras you would end up with the equation given where the 4 is in fact r2 To obtain the plot points manipulate the equation as below Given x2 y2 = r2 → x2 y2 = 4 Subtract x2 from both sides giving y2 = 4 −x2 Take the square root of both sides y = √4 − x2 Now write it as y = ± √4 −x2Answers Click here to see ALL problems on Rationalfunctions Question 444 graph the parabola y= (x5)^2 4 Answer by venugopalramana (3286) ( Show Source ) You can put this solution on YOUR website!Swap sides so that all variable terms are on the left hand side x^ {2}2x=y4 Subtract 4 from both sides x^ {2}2x1^ {2}=y41^ {2} Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of
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Graph the parabola y= (x5)^2 44 5 6 \times \arctan \tan \log 1 2 3\pi e x^{\square} 0 \bold{=} Go Related » Graph » Number inverse y=x^{2}4 en Related Symbolab blog posts Functions A function basically relates an input to an output, there's an input, a relationship and an output For every inputSubtract y from both sides x^ {2}4x4y=0 x 2 4 x 4 − y = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 4 for b, and 4y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} This equation is in standard form a x 2 b x c = 0 Substitute 1 for a, 4 for b, and 4 − y for c in the quadratic
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Find the absolute value vertex In this case, the vertex for y = x−2−4 y = x 2 4 is (2,−4) ( 2, 4) Tap for more steps To find the x x coordinate of the vertex, set the inside of the absolute value x − 2 x 2 equal to 0 0 In this case, x − 2 = 0 x 2 = 0 Add 2 2 to both sides of the equationGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!Suppose the curves are x = y2 and x = 4 y2 and and you want to find points on the two curves with the same yvalue Then substitute y 2 from the first equation into the second to obtain x = 4 x So to achieve the same yvalue the xvalue on the second curve must be (minus) 4 times the xvalue on the first curve x = 4y2 and x = y2
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Hint Drag to pan Mouse wheel to zoomY=a (x2) (x4) Simple and best practice solution for y=a (x2) (x4) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itSee all questions in Quadratic Functions and Their Graphs Impact of
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How do you find the xcoordinate of the vertex for the graph #4x^216x12=0#?Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyEquations Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations xy=2;2x2y=4 so that you understand better
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It can be solved by adding these two equations So that we can cancel one variable (here we can cancel variable y by adding the equation) Note you can also substract But lets add to make things easy Adding the two equations (XY)(xy)=24 Vertex(0,4) y=x^24 If the equation of a parabola is in the form y=ax^2bxc we can find the xcoordinate of its vertex using the following formula x_(vertex)=b/(2a) Comparing the problem equation with the form above, we see a=1, b=0, c=4 x_(vertex)=0/(2(1))=0 Now, we can plug this into the equation to find the ycoordinate y_(vertex)=(0)^24=04=4 Therefore, Vertex(0,4Complete set of values of 'a' for which 4 x − a 2 x − a 2 < 0 has atleast one solution in (1,2) is View solution If a b c = 9 and a b b c c a = 4 0 , find a 2 b 2 c 2
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x^4 x^2 1 = (x^2 x 1)(x^2 x 1) To find this, first notice that x^4 x^2 1 > 0 for all (real) values of x So there are no linear factors, only quadratic ones x^4 x^2 1 = (ax^2 bx c)(dx^2 ex f) Without bothering to multiply this out fully just yet, notice that the coefficient of x^4 gives us ad = 1 We might as well let a = 1 and d = 1 = (x^2 bx c)(x^2How do you know if #y=164x^2# opens up or down?Free Parabola calculator Calculate parabola foci, vertices, axis and directrix stepbystep
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Y = x^2, y = 4, about y = 4Find the volume of the solid obtained by rotating theregion bounded by the given curves about the specified line Sketchthe regionCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyCompute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, history
Quadratic Function
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How to Check Your Answer with Algebra Calculator First go to the Algebra Calculator main page Type the following First type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 How do you graph #y=x^22x3#?Simple and best practice solution for y4=2(x1) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,
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Simple and best practice solution for x2y=4 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand,Graph the parabola, y =x^21 by finding the turning point and using a table to find values for x and yGraph y=(x2)^24 Find the properties of the given parabola Tap for more steps Use the vertex form, , to determine the values of , , and Since the value of is positive, the parabola opens up Opens Up Find the vertex Find , the distance from the vertex to the focus Tap for more steps
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